轉(zhuǎn)動(dòng)慣量測量實(shí)驗(yàn)報(bào)告(共7篇)

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1 2 3 .: 1 m = i (1) 2 amg C t=math=at/2trmftr - mf = ia = r 22m(g - a)r - mf = 2hi/rt (2) mfma<<g 2mgr = 2hi/ rt (3) rhtm3i 3 3 2am C 1/tr h3 2m = k1/ t (4) 2k1 = 2hi/ grt m1/t 222m C 1/tk1hrgk1 = 2hi/ gri br C 1/tmh3 r = k2/ t 5 k2 = (2hi/ mg)r1/trtr1/t 1/21/2r1/tmhgk2 = (2hi/ mg)i. . . 1. h 2. 3.00cm20gh 3. t 5.0g 5g5g35g 4. . r-1/t i=1.78?10?3kg?m 2 m-(1/t)2 i=1.87?10?3kg?m2 . r-1/ti=1.78?10 m-1/ti=1.87?10?3kg?m2. 2?3kg?m;2 . 1 2 3 4aa<<g . 1. 1001 201009110024 201009110059 ?201009110019 1. 2. k 3. 1 2 3 4 5hld-th-ii 0.001ms 1. 1 23 m b mk 1 k mi i? ?2 ? m 2 ? k ,12 d2?k2 ??????? 3??2 idt acos(t) 4 a t? 2? ? ?2? i 5 k 5ik k3 2. k 1t05 2t15 3 3. 4 miox i=icmx2(6) k 1 2 3t0 4t1 5t2 2 1t3 25.0010.0015.0020.0025.00t s=ks= =0.000058 s==0.00115 s==0.5773 t0=1.04140.000058 kg* = = =0.01 k=0.0192760.01 kg* i2==0.01 kg* = 1.61836* kg* e=30.4% 2. - 1 (1) 2 2 1 2 2 2 3 3 2 4 1 2 3 4+ 5 : 0.01s 1 2 3 1 2 1 2 3 10.01s20 2 3 4 () 1 m = i (1) 2 amg C t=math=at/2trmftr - mf = ia = r m(g - a)r - mf = 2hi/rt(2) mfma<<g mgr = 2hi/ rt(3) rhtm3i 3 3 am C 1/trh3 m = k1/ t(4) k1 = 2hi/ grtm1/t 2 2 2 2 2 2 2 m C 1/tk1hrgk1 = 2hi/ gri br C 1/tmh3 r = k2/ t5 k2 = (2hi/ mg)r1/trtr1/t r1/tmhgk2 = (2hi/ mg)i a. ba c. 1. h 2. 3.00cm20gh 3. t 5.0g 1/2 1/2 2 2 5g5g35g n 4. 1m-1/t2 2r1/t ---131006231- dh4601 j??r2dm j??ri2?mi 1 1. ,, 2. oo oo i0=t02m0grr/42h0 m0rr h0togg=9.788m/s2 moo t1hoo i1=t12[(m0+m)grr]/42h hh0 : i=i1i0-=[(t12 (m0+m)- t02m0)grr]/42h0 oo? 1. (1) dh4601 n = 30 ()2n + 1()n 50250+1=101 (2) 50 ()n , ()50 (3) 30 2. 1 2a 3() 4 a b r r r=a/3,r=b/3 5ho 6ooto ()5(n = 50) 7t1 t1 8() 1 mo= m= ho= 2 ooi i=i1i0-=[(t12 (m0+m)- t02m0)grr]/42h0 i= 5 2 oooo i0=t02m0grr/42h0 m0rr h0 togg=9.788m/s2 1rxyz 2 2