高中數(shù)學(xué) 第三章 導(dǎo)數(shù)應(yīng)用 3.2導(dǎo)數(shù)在實(shí)際問(wèn)題中的應(yīng)用 3.2.2.2 導(dǎo)數(shù)在實(shí)際問(wèn)題中的應(yīng)用課件 北師大版選修22

《高中數(shù)學(xué) 第三章 導(dǎo)數(shù)應(yīng)用 3.2導(dǎo)數(shù)在實(shí)際問(wèn)題中的應(yīng)用 3.2.2.2 導(dǎo)數(shù)在實(shí)際問(wèn)題中的應(yīng)用課件 北師大版選修22》由會(huì)員分享，可在線(xiàn)閱讀，更多相關(guān)《高中數(shù)學(xué) 第三章 導(dǎo)數(shù)應(yīng)用 3.2導(dǎo)數(shù)在實(shí)際問(wèn)題中的應(yīng)用 3.2.2.2 導(dǎo)數(shù)在實(shí)際問(wèn)題中的應(yīng)用課件 北師大版選修22（28頁(yè)珍藏版）》請(qǐng)?jiān)谘b配圖網(wǎng)上搜索。

1、第2 2課時(shí)導(dǎo)數(shù)在實(shí)際問(wèn)題中的應(yīng)用MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理1.了解導(dǎo)數(shù)在解

2、決實(shí)際問(wèn)題中的作用.2.掌握利用導(dǎo)數(shù)解決簡(jiǎn)單的實(shí)際生活中的優(yōu)化問(wèn)題.MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI

3、SHULI知識(shí)梳理1.解決實(shí)際問(wèn)題的關(guān)鍵在于建立數(shù)學(xué)模型和目標(biāo)函數(shù),把“問(wèn)題情境”譯為“數(shù)學(xué)語(yǔ)言”,找出問(wèn)題的主要關(guān)系,抽象成數(shù)學(xué)問(wèn)題,然后用可導(dǎo)函數(shù)求最值的方法求最值.2.解決優(yōu)化問(wèn)題的基本思路.上述解決優(yōu)化問(wèn)題的過(guò)程是一個(gè)典型的數(shù)學(xué)建模過(guò)程.MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DI

4、ANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理解析:由題設(shè)知y=x2-39x-40,所以當(dāng)x=40時(shí),y取得極小值,也是最小值.故為使耗電量最小,其速度應(yīng)定為40.答案:40MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析

5、SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四【例1】 為了在夏季降溫和冬季供暖時(shí)減少能源損耗,房屋的屋頂和外墻需要建造隔熱層.某幢建筑物要建造可使用20年的隔熱層,每厘米厚的隔熱層建造成本為6萬(wàn)元.該建筑物每年的能源消耗費(fèi)用C(單位:萬(wàn)元)與隔熱層厚度x(單位:cm)滿(mǎn)足關(guān)系:C(x)= (0 x10).若不建隔熱層,每年能源消耗費(fèi)用為8萬(wàn)元.

6、設(shè)f(x)為隔熱層建造費(fèi)用與20年的能源消耗費(fèi)用之和.(1)求k的值及f(x)的表達(dá)式;(2)當(dāng)隔熱層修建多厚時(shí),總費(fèi)用f(x)達(dá)到最小,并求最小值.分析:根據(jù)題設(shè)條件構(gòu)造函數(shù)關(guān)系,再應(yīng)用導(dǎo)數(shù)求最值.MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYAN

7、LIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISH

8、ISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四反思反思解決應(yīng)用問(wèn)題時(shí),步驟“設(shè)、列、解”缺一不可,寫(xiě)出函數(shù)關(guān)系式及定義域后用導(dǎo)數(shù)求最值,解決最值問(wèn)題.MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)

9、航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四【變式訓(xùn)練1】 一艘輪船在航行時(shí)每小時(shí)的燃料費(fèi)和它的速度的立方成正比.已知速度為每小時(shí)10海里時(shí),燃料費(fèi)是每小時(shí)6元,而其他與速度無(wú)關(guān)的費(fèi)用是每小時(shí)96元,問(wèn)輪船的速度是多少時(shí),航行1海里所需的費(fèi)用總和最小?MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典

10、例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYAN

11、LIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四【例2】 某廠(chǎng)生產(chǎn)某種電子元件,如果生產(chǎn)出一件正品,那么可獲利200元,如果生產(chǎn)出一件次品,那么損失100元.已知該廠(chǎng)制造電子元件過(guò)程中,次品率p與日產(chǎn)量x的函數(shù)關(guān)系是 (xN+),(1)將該廠(chǎng)的日盈利額T(單位:元)

12、表示為日產(chǎn)量x(單位:件)的函數(shù);(2)為獲最大盈利,該廠(chǎng)的日產(chǎn)量應(yīng)定為多少件?分析:根據(jù)次品率,先計(jì)算出正品數(shù)與次品數(shù),再用獲利總數(shù)減去損失總數(shù)可得盈利.MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳

13、理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITO

14、UXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四反思反思解決此類(lèi)有關(guān)利潤(rùn)的實(shí)際應(yīng)用題,應(yīng)靈活運(yùn)用題設(shè)條件,建立利潤(rùn)的函數(shù)關(guān)系,常見(jiàn)的基本等量關(guān)系有:(1)利潤(rùn)=收入-成本;(2)利潤(rùn)=每件產(chǎn)品的利潤(rùn)銷(xiāo)售件數(shù).MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知

15、識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLI

16、TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUIT

17、ANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四【例3】 如圖,要設(shè)計(jì)一張矩形廣告,該廣告含有大小相等的左右兩個(gè)矩形欄目(即圖中陰影部分),這兩欄的面積之和為18 000 cm2,四周空白的寬度為10 cm,兩欄之間的中縫空白的寬度為5 cm.怎樣確定廣告的高與寬的尺寸(單位:cm),能使矩形廣告的面積最小?分析:設(shè)出適當(dāng)?shù)淖兞?把廣告面積用該變量表示出來(lái),然后用導(dǎo)數(shù)解答最值問(wèn)題.MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITAN

18、GYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練Z

19、HISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四令S0,得x140;令S0,得20 x140.函數(shù)在(140,+)上是增加的,在(20,140)上是減少的,S(x)的最小值為 S

20、(140).當(dāng)x=140時(shí),y=175,即當(dāng)x=140,y=175時(shí),S取得最小值24 500 cm2.故當(dāng)廣告的高為140 cm,寬為175 cm時(shí),可使廣告的面積最小.反思反思解決面積、容積的最值問(wèn)題,要正確引入變量,將面積或容積表示為變量的函數(shù),結(jié)合實(shí)際問(wèn)題的定義域,利用導(dǎo)數(shù)求解函數(shù)的最值.MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIA

21、N隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四【變式訓(xùn)練3】 用長(zhǎng)為90 cm,寬為48 cm的長(zhǎng)方形鐵皮做一個(gè)無(wú)蓋的容器,先在四個(gè)角分別截去一個(gè)小正方形,再把四邊翻轉(zhuǎn)90,然后焊接成如圖所示的容器,問(wèn)該容器的高為多少時(shí),容器的容積最大?最大容積是多少?MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SH

22、ULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四解:設(shè)容器的高為x cm,容器的容積為V(x)cm3.則V(x)=x(90-2x)(48-2x)=4x3-276x2+4 320 x(0 x24)

23、.V(x)=12x2-552x+4 320=12(x2-46x+360)=12(x-10)(x-36)(0 x24).令V(x)=0,得x1=10,x2=36(舍去).當(dāng)0 x0,V(x)是增加的;當(dāng)10 x24時(shí),V(x)0,V(x)是減少的.因此,在定義域(0,24)內(nèi),函數(shù)V(x)只有在x=10處取得最大值,其最大值為V(10)=10(90-20)(48-20)=19 600.故當(dāng)容器的高為10 cm時(shí),容器的容積最大,最大容積是19 600 cm3.MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)

24、導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四易錯(cuò)點(diǎn):應(yīng)用函數(shù)模型時(shí),不注意實(shí)際問(wèn)題的定義域而致錯(cuò)【例4】 現(xiàn)有一批貨物由海上從A地運(yùn)往B地,已知輪船的最大航行速度為35海里/時(shí),A地至B地之間的航行距離約為5

25、00海里,每小時(shí)的運(yùn)輸成本由燃料費(fèi)和其余費(fèi)用組成,輪船每小時(shí)的燃料費(fèi)與輪船速度的平方成正比(比例系數(shù)為0.6),其余費(fèi)用為每小時(shí)960元.(1)把全程運(yùn)輸成本y(單位:元)表示為速度x(單位:海里/時(shí))的函數(shù).(2)為了使全程運(yùn)輸成本最小,輪船應(yīng)以多大速度行駛?MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)

26、梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLIT

27、OUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理題型一題型二題型三題型四MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITA

28、NGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理1 2 3 4 5MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHI

29、SHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理1 2 3 4 5MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航

30、DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理1 2 3 4 53已知某生產(chǎn)廠(chǎng)家的年利潤(rùn)y(單位:萬(wàn)元)與年產(chǎn)量x(單位:萬(wàn)件)之間的函數(shù)關(guān)系式為y=- x3+81x-234,則使該生產(chǎn)廠(chǎng)家獲取最大年利潤(rùn)的年產(chǎn)量為()A.13萬(wàn)件B.11萬(wàn)件C.9萬(wàn)件D.7萬(wàn)件解析:y=-x2+81,令y=0,得x=9(x=-9舍去),且經(jīng)討論知x=9是函數(shù)的極大值點(diǎn),也是最大值點(diǎn),故廠(chǎng)家獲得最大年利潤(rùn)的年產(chǎn)量是9萬(wàn)件.答案:CMUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理

31、目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理1 2 3 4 5MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典

32、例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理1 2 3 4 5MUBIAODAOHANG目標(biāo)導(dǎo)航DIANLI TOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHI SHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGYANLIAN隨堂演練ZHISHISHULI知識(shí)梳理1 2 3 4 5